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('b' + 'a' + + 'a' + 'a').toLowerCase() 'banana' 우왕

https://school.programmers.co.kr/learn/courses/30/lessons/181187 파이썬 def solution(r1, r2): answer = 0 pow_r1, pow_r2 = r1 ** 2, r2 ** 2 for y in range(1, r2 + 1): temp1 = pow_r1 - y ** 2 if temp1 >= 0: temp2 = temp1 ** 0.5 x1 = int(temp2) - (1 if temp2 == int(temp2) else 0) else: x1 = -1 answer += int((pow_r2 - y ** 2) ** 0.5) - x1 return answer * 4

https://school.programmers.co.kr/learn/courses/30/lessons/181188 파이썬 def solution(targets): answer, defense = 0, 100_000_001 for start, end in sorted(targets, reverse=True): if end

https://school.programmers.co.kr/learn/courses/30/lessons/178870 파이썬 이렇게 쉽게는 넘어가지 않겠지.. def solution(sequence, k): answer = [] for i in range(len(sequence)): for j in range(i + 1, len(sequence) + 1): s = sum(sequence[i:j]) if s == k: answer.append([i, j - 1]) elif s > k: break return sorted(answer, key=lambda x: x[1] - x[0])[0] 소티드를 이용해서 간결하게.. def solution(sequence, k): answer = [] left = right..

https://school.programmers.co.kr/learn/courses/30/lessons/178871 파이썬 def solution(players, callings): players_map = {each: index for index, each in enumerate(players)} for player in callings: index = players_map[player] players_map[player] -= 1 players_map[players[index - 1]] += 1 players[index - 1], players[index] = players[index], players[index - 1] return players 계속 find 명령을 쓰면 시간이 너무 오래 걸린다...

https://school.programmers.co.kr/learn/courses/30/lessons/176962 파이썬 def solution(plans): timeline = [] plans2 = map(lambda x: (x[0], int(x[1][0]) * 60 + int(x[1][1]), x[2]), map(lambda x: (x[0], x[1].split(':'), int(x[2])), plans)) for name, start, playtime in sorted(plans2, key=lambda x: x[1]): for index, each in enumerate(timeline): if each[1] > start: timeline[index][1] += playtime timeline...

https://school.programmers.co.kr/learn/courses/30/lessons/176963 파이썬 def solution(name, yearning, photo): scores = {n: s for n, s in zip(name, yearning)} return [sum(scores.get(person, 0) for person in pic) for pic in photo] def solution(name, yearning, photo): return [sum({n: s for n, s in zip(name, yearning)}.get(person, 0) for person in pic) for pic in photo] 코틀린 class Solution { fun solution..

dependencies: http: ^0.13.5 import 'package:flutter/rendering.dart'; import 'package:http/http.dart' as http; void main() async { // https://jsonplaceholder.typicode.com/todos/1 final httpsUri = Uri( scheme: 'https', host: 'jsonplaceholder.typicode.com', path: 'todos/1'); var response = await http.get(httpsUri); debugPrint('${response.statusCode}'); debugPrint(response.body); } import 'package:f..