테이블 해시 함수

https://school.programmers.co.kr/learn/courses/30/lessons/147354

from functools import reduce

solution = lambda data, col, row_begin, row_end: reduce(lambda x, y: x ^ y, (sum(each % (i + 1) for each in sorted(data, key=lambda x: (x[col - 1], -x[0]))[i]) for i in range(row_begin - 1, row_end)))

def solution(data, col, row_begin, row_end):
    data.sort(key=lambda x: (x[col - 1], -x[0]))
    answer = None
    for i in range(row_begin - 1, row_end):
        si = sum(each % (i + 1) for each in data[i])
        answer = si if answer is None else answer ^ si
    return answer