파이썬 날코딩: XOR 문제

논리 연산으로.. 

def AND(x1, x2):
    return x1 and x2


def NAND(x1, x2):
    return not (x1 and x2)


def OR(x1, x2):
    return x1 or x2


def XOR(x1, x2):
    return AND(NAND(x1, x2), OR(x1, x2))


for each in ((False, False), (True, False), (False, True), (True, True)):
    print(each, XOR(*each))

가중치와 바이어스를 이용해.. 

def MLP(x1, x2, w, b):
    if w * x1 + w * x2 + b > 0:
        return 1
    return 0


def AND(x1, x2):
    return MLP(x1, x2, 1, -1)


def NAND(x1, x2):
    return MLP(x1, x2, -2, 3)


def OR(x1, x2):
    return MLP(x1, x2, 2, -1)


def XOR(x1, x2):
    return AND(NAND(x1, x2), OR(x1, x2))


for each in ((0, 0), (1, 0), (0, 1), (1, 1)):
    print(each, XOR(*each))