프로그래머스 / 햄버거 만들기

https://school.programmers.co.kr/learn/courses/30/lessons/133502

파이썬

def solution(ingredient):
    stack = []
    answer = 0
    for each in ingredient:
        stack.append(each)
        if stack[-4:] == [1, 2, 3, 1]:
            answer += 1
            del stack[-4:]
    return answer

 

코틀린

class Solution {
    fun solution(ingredient: IntArray): Int {
        var answer = 0
        val bugger = listOf(1, 2, 3, 1)
        val stack = mutableListOf<Int>()
        for (each in ingredient) {
            stack.add(each)
            if (stack.size >= 4 && stack.slice(stack.size - 4 until stack.size) == bugger) {
                repeat(4) { stack.removeLast() }
                answer++
            }
        }
        return answer
    }
}