25. 정수 제곱근 판별

https://programmers.co.kr/learn/courses/30/lessons/12934

 

파이썬

def solution(n):
    x = n**0.5
    return -1 if (x % 1) else (x+1)**2

자바스크립트

function solution(n) {
    let num = Math.sqrt(n)
    return (num == parseInt(num)) ? (num + 1) ** 2 : -1
}

자바

class Solution {
    public long solution(long n) {
        var a = (long) Math.sqrt(n);
        return (a * a == n) ? (a + 1) * (a + 1): -1;
    }
}

고

import "math"

func solution(n int64) int64 {
	var x = int64(math.Sqrt(float64(n)))
	if x*x == n {
		return (x + 1) * (x + 1)
	}
	return -1
}

코틀린

import kotlin.math.sqrt

class Solution {
    fun solution(n: Long): Long {
        val a = sqrt(n.toDouble()).toLong()
        return if (a * a == n) (a + 1) * (a + 1) else -1
    }
}

C#

using System;

public class Solution
{
    public long solution(long n)
    {
        long temp = (long)Math.Sqrt((double)n);
        return (temp * temp == n) ? (temp + 1) * (temp + 1) : -1;
    }
}