30. 정수 내림차순으로 배치하기

https://programmers.co.kr/learn/courses/30/lessons/12933

 

파이썬

def solution(n):
    return int(''.join(sorted(str(n), reverse=True)))

자바스크립트

function solution(n) {
    return Number(String(n).split('').sort((a, b) => a <= b ? 1 : -1).join(''))
}

자바

import java.util.Arrays;

class Solution {
    public long solution(long n) {
        var numbers = String.valueOf(n).split("");
        Arrays.sort(numbers);
        String temp = "";
        for (var each : numbers) {
            temp = each + temp;
        }
        return Long.valueOf(temp);
    }
}

import java.util.*;

class Solution {
    public long solution(long n) {
        return Long.parseLong(
                Arrays.stream(String.valueOf(n).split(""))
                        .sorted(Comparator.reverseOrder())
                        .reduce("", String::concat)
        );
    }
}

코틀린

class Solution {
    fun solution(n: Long): Long = n.toString().toCharArray().sortedDescending().joinToString("").toLong()
}

고

import "sort"
func solution(n int64) (result int64) {
	var temp []int
	for n > 0 {
		temp = append(temp, int(n%10))
		n /= 10
	}
	sort.Sort(sort.Reverse(sort.IntSlice(temp)))
	for _, v := range temp{
		result = result * 10 + int64(v)
	}
	return
}

C#

using System;
using System.Linq;

public class Solution
{
    public long solution(long n) {
        char[] temp = n.ToString().ToArray();
        Array.Sort(temp);
        Array.Reverse(temp);
        return long.Parse(temp); 
    }
}

using System;
using System.Linq;

public class Solution
{
    public long solution(long n) => 
        long.Parse(n.ToString().OrderBy(x => x).Reverse().ToArray());
}