프로그래머스 / 콜라 문제

https://school.programmers.co.kr/learn/courses/30/lessons/132267

파이썬

def solution(a, b, n):
    answer = 0
    while n >= a:
        quotient = n // a  # 몫
        new_bottle = quotient * b  # 새 콜라
        n -= a * quotient  # 마트에 가져다 준 빈 병
        answer += new_bottle
        n += new_bottle
    return answer

import sys

sys.setrecursionlimit(10000)


def solution(a, b, n):
    if n < a:
        return 0
    quotient = n // a
    new_bottle = quotient * b
    return new_bottle + solution(a, b, n - a * quotient + new_bottle)

 

코틀린

class Solution {
    fun solution(a: Int, b: Int, n: Int): Int {
        var answer = 0
        var nn = n
        while (nn >= a) {
            val quotient = nn / a
            val newBottle = quotient * b
            nn -= a * quotient
            nn += newBottle
            answer += newBottle
        }
        return answer
    }
}

class Solution {
    fun solution(a: Int, b: Int, n: Int): Int {
        if (n < a) {
            return 0
        }
        val quotient = n / a
        val newBottle = quotient * b
        return newBottle + solution(a, b, n - a * quotient + newBottle)
    }
}